The distance travelled by an object is given by x=(at+bt^{2})/(c+a) where t is time and a,b,c are constants. The dimension of b and c respectively are:

- [L
^{2}T^{-3}], [LT^{-1}] - [LT
^{-2}], [LT^{-1}] - [LT
^{-1}], [L^{2}T^{1}] - [LT
^{-1}], [LT^{2}]

**Solution:**

The dimension of x is L. Hence, the dimension of a must be LT^{-1}.

Dimension of c and a are the same.

Dimension of b therefore is L^{2}T^{-3}.