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May 17, 2017

Dimensional Analysis

The distance travelled by an object is given by x=(at+bt2)/(c+a) where t is time and a,b,c are constants. The dimension of b and c respectively are:

  • [L2T-3], [LT-1]
  • [LT-2], [LT-1]
  • [LT-1], [L2T1]
  • [LT-1], [LT2]

Solution:

The dimension of x is L. Hence, the dimension of a must be LT-1.

Dimension of c and a are the same.

Dimension of b therefore is L2T-3.

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