Try this problem from American Invitational Mathematics Examination, AIME, 2019 based on Combinations
Combinations- AIME, 2009
A game show offers a contestant three prizes A B and C each of which is worth a whole number of dollars from $1 to $9999 inclusive. The contestant wins the prizes by correctly guessing the price of each prize in the order A B and C. As a hint the digits of three prizes are given. On a particular day the digits given were 1,1,1,1,3,3,3. Find the total number of possible guesses for all three prizes consistent with the hint.
- 110
- 420
- 430
- 111
Key Concepts
Combinations
Theory of equations
Polynomials
Check the Answer
But try the problem first…
Answer: 420.
AIME, 2009
Combinatorics by Brualdi .
Try with Hints
First hint
Number of possible ordering of seven digits is$\frac{7!}{4!3!}$=35
Second hint
these 35 orderings correspond to 35 seven-digit numbers, and the digits of each number can be subdivided to represent a unique combination of guesses for A B and C. Thus, for a given ordering, the number of guesses it represents is the number of ways to subdivide the seven-digit number into three nonempty sequences, each with no more than four digits. These subdivisions have possible lengths 1/2/4,2/2/3,1/3/3, and their permutations. The first subdivision can be ordered in 6 ways and the second and third in three ways each, for a total of 12 possible subdivisions.
Final Step
then total number of guesses is 35.12=420
Other useful links
- https://www.cheenta.com/geometry-of-plane-figures-pre-rmo-2019/
- https://www.youtube.com/watch?v=65RRPvbATsk
Related Program
Math Olympiad Program… taught by Olympians and researchers
