**Problem:**

The number of terms in the expression of

\([(a+3b)^2 (a-3b)^2]^2 \)

A) 4;

B) 5;

C) 6;

D) 7;

**Solution:**

\([(a+3b)^2 (a-3b)^2]^2 \)

\(= [\{(a+3b)(a-3b)\}^2]^2 \)

\(= \{ (a^2 -9b^2)^2\}^2 = (a^2 – 9b^2)^4 \)

By Binomial Theorem, the given expression contains 5 terms (since \((x +y)^n \) has n+1 terms in general).

**Answer: B) 5;**