The number of different factors of 1800 equals:
(A) 12; (B) 210; (C) 36; (D) 18;
We may factor 1800 as \(2^3 \times 3^2 \times 5^2 \)
Then the number of factors is: \((3+1) \times (2+1) \times (2+1) = 36 \)
Hence answer is 36.
- What is this topic: Number Theory
- What are some of the associated concept: Number Theoretic Functions
- Where can learn these topics: Cheenta I.S.I. & C.M.I. course, discusses these topics in the ‘Number Theory’ module.
- Book Suggestions: Elementary Number Theory by David Burton