**Problem: **Draw the graph (on plain paper) of f(x)= min { |x| -1, |x-1| – 1, |x-2|-1}

**Discussion: **The easiest way to solve this problem is to draw the graph of all these three pieces of functions mentioned, and pick ones which are minimum.

Graph of y = |x| is same as, y = x, where x is non negative. For negative values of x, it is the graph of y = x reflected about x axis.

Now we apply transformations to find the remaining graphs.

- Graph of y = |x|-1 can be found by
*lowering*the graph of y = |x| by 1 unit along y axis. - Graph of y = |x-1| – 1 can be found by first shift the graph of y = |x| along positive direction of x axis by 1 unit, and then lowering it by 1 unit along y axis.
- Graph of y = |x-2| – 1 can be found by first shift the graph of y = |x| along positive direction of x axis by 2 unit, and then lowering it by 1 unit along y axis.

Now we will plot all the graphs together and then consider the portion which are ‘lowest’.

(all of them together)

(considering only the minimum portions)

### Comment:

There is a rigorous way of doing this problem.

- First we consider the inequality |x| – 1 < |x-1| – 1. This implies |x| < |x – 1|. Here we need to split the domain into three pieces.
- \(x \le 0 \). This is implies |x| = – x and |x-1| = -(x-1). Therefore – x < -(x-1) or 0 < 1. This is always true. Hence for all values of \(x \le 0 \), \(|x| – 1 < |x-1|-1 \)
- \(0 \le x \le 1 \). This is implies |x| = x and |x-1| = -(x-1).Therefore \(x \le -(x-1) \) or \(2x \le 1\) or \(x \le \frac{1}{2} \). Hence upto x = 1/2 we consider the graph of |x|-1. From x=1/2 to 1, we will consider the graph of |x-1|-1
- Finally we will take the case where x > 1

- Like this we consider each pair of expression and solve the inequalities.
- Finally graph whichever in lowest in whatever piece of the domain.

## Chatuspathi:

**What is this topic:**Graphing Techniques**What are some of the associated concept:**Absolute Value Function, Domain splitting, Transformation of Graphs**Where can learn these topics:**Cheenta**Book Suggestions:**Play With Graphs (Arihant Publication)